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Dec 29, 2019 at 12:07 comment added Hermann Gruber +1: I changed my mind after considering Gil Kalai's comments and re-reading the accepted answer. Those nonlinear lower bounds are only known if the tapes are conceptually infinite only to the right (akin to the set $\mathbb N$) and not bi-infinite (like the set $\mathbb Z$). Somehow this provably causes overhead for moving the read/write head. For random access machines, moving the read/write head comes "for free" by definition.
Dec 24, 2019 at 21:37 comment added Gil Kalai @HermannGruber, I suppose that for random access Turing machines the best known lower bounds are linear, right?
Dec 24, 2019 at 21:36 history edited Gil Kalai CC BY-SA 4.0
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Dec 24, 2019 at 11:49 comment added Hermann Gruber Thanks for commenting years after your answer! The accepted answer cites a superlinear lower bound for multitape Turing machines. I agree that circuit lower bounds are important, but it is a different model than what was asked for.
Dec 24, 2019 at 10:58 comment added Gil Kalai @HermannGruber yes indeed my answer was based on what I know for circuits (as elaborated in my comment). But I believe nothing better is known for the (general) Turing machine model. If you know otherwise please let us know. In any case the circuit model is important so the answer is very relevant to the question.
Dec 24, 2019 at 8:59 comment added Hermann Gruber -1: Your answer concerns nonuniform circuit families, not Turing machines or RAMs.
Nov 29, 2009 at 21:22 vote accept Rune
Dec 18, 2009 at 20:21
Nov 21, 2009 at 14:20 comment added Gil Kalai Here is a citation and a link : Uri Zwick, A 4n lower bound on the combinatorial complexity of certain symmetric Boolean functions over the basis of unate dyadic Boolean functions SIAM Journal on Computing 20, 499-505 (1991) An explicit lower bound of 5n-o (n) for boolean circuits, K Iwama, O. Lachish, H Morizumi, and R. Raz springerlink.com/index/XCP1TCRY1C236RDT.pdf The introduction of the second paper and the slow incremental improvements may give some idea on the difficulty of the problem.
Nov 14, 2009 at 22:23 comment added Sam Nead Could you flesh this out? Or give a link to a reference? Why is finding super-linear lower bounds hard? If it is obvious, I apologize in advance.
Nov 11, 2009 at 6:10 history answered Gil Kalai CC BY-SA 2.5