Timeline for Is a subset that contains no positive measurable subsets contained in a null measurable set?
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
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| Dec 18, 2010 at 2:15 | vote | accept | ronggang | ||
| Dec 17, 2010 at 15:40 | comment | added | Andrés E. Caicedo | On the other hand, if one assumes determinacy (that contradicts choice), then the result is true (at least in any decent space). For example, for the reals we in fact have that if the only Borel subsets of $A$ are measure zero, then $A$ is contained in a Borel set of measure zero. Note that Joel's argument does not use choice after the first paragraph. | |
| Dec 17, 2010 at 5:19 | history | edited | Joel David Hamkins | CC BY-SA 2.5 |
fixed error regarding finiteness of measure
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| Dec 17, 2010 at 4:57 | history | answered | Joel David Hamkins | CC BY-SA 2.5 |