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Dec 15, 2010 at 22:22 comment added Vaughn Climenhaga It doesn't look to me as though any value of s makes the generalised Kneser graph fit Tyson's criteria. They fail on two counts: (1) the vertex sets should be ordered tuples, not subsets, as already observed, and (2) the adjacency criterion would need to be specify the size of the intersection exactly (as $k-1$) rather than merely giving an upper bound ($\leq s$).
Dec 15, 2010 at 19:51 comment added Tyson Williams Yes, I read that. Are you saying that the graph I described and the Kneser graph have the same number of vertices?
Dec 15, 2010 at 19:48 comment added Igor Rivin The below is a paste from the wikipedia article: The generalized Kneser graph KGn,k,s has the same vertex set as the Kneser graph KGn,k, but connects two vertices whenever they correspond to sets that intersect in s or fewer items (Denley 1997). Thus KGn,k,0 = KGn,k.
Dec 15, 2010 at 19:42 comment added Tyson Williams Are you sure? The graph the I am looking for has n!/(n-k)! vertices, but the Kneser graph (and its generalization) have (n choose k).
Dec 15, 2010 at 19:31 history answered Igor Rivin CC BY-SA 2.5