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Apr 4, 2012 at 10:24 history edited KP Hart CC BY-SA 3.0
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Dec 19, 2010 at 15:33 comment added mathahada An easy construction of an almost disjoint family of size continuum is given by taking, for each real number with, say, decimal expansions 0.123411... the set {1, 12, 123, 1234, ... }.
Dec 14, 2010 at 22:36 comment added Stefan Geschke KP, this is my favorite proof among several very nice arguments so far. Thanks for the answer.
Dec 14, 2010 at 14:58 comment added gowers An obvious remark to make here is that all you need as your starting point is continuum-many subsets of a countable set with all intersections finite: thus, the binary tree is one of many constructions that will do the job. It's nice to see such a direct link between the two problems.
Dec 14, 2010 at 11:54 history answered KP Hart CC BY-SA 2.5