Skip to main content
7 events
when toggle format what by license comment
Nov 11, 2009 at 4:02 comment added David E Speyer No to the second. Kaehler plus Moishezon = projective, and not all smooth toric varieties are projective. I think no to the first, but I need to think about it. (Or wait for some else to answer.)
Nov 10, 2009 at 23:37 comment added Kevin H. Lin Is it true that (compact if needed) smooth toric varieties are always symplectic? Are all (compact if needed) smooth toric varieties Kaehler?
Nov 10, 2009 at 22:56 comment added David E Speyer I should have said "compact n-dimensional smooth toric variety" in the above answer.
Nov 10, 2009 at 22:53 comment added David E Speyer The cohomology of a n-dimensional smooth toric variety is given by the same recipe whether or not it is projective: one generator x(i), in degree 2, for each ray rho(i) of the fan. The relations are that $x(i\_1) ... x(i\_k) =0$ whenever the rays rho(i_1) ... rho(i_k) do not lie in a common cone, combined with n linear relations that are a little too complicated to write here. (See Fulton's book.) The first set of relations is in degree larger than 2, so H^2 has dimension (number of rays)-n, which is always greater than 0.
Nov 10, 2009 at 22:49 comment added David E Speyer A compact complex manifold without $H^2$ is not algebraic. See a sketch of a proof here: sbseminar.wordpress.com/2008/02/14/…
Nov 10, 2009 at 22:27 comment added Greg Kuperberg A projective structure on a toric variety is given by a rational convex polytope structure on its fan. When its fan is complete but non-regular, the variety is proper but not projective. But I don't know how to compute H^2 of this, although I'm sure lots of people do. However, an even-dimensional simple Lie group such as SU(3) has left-invariant complex structures, and these immediately have no H^2.
Nov 10, 2009 at 20:52 history answered Kevin H. Lin CC BY-SA 2.5