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Dec 13, 2010 at 15:05 history edited Andrey Rekalo
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Dec 13, 2010 at 9:02 comment added David Feldman @Aaron Perhaps if there were some natural abstract connection between $\ell^p$ and $\ell^{p^2}$, you'd have a winner.
Dec 13, 2010 at 9:00 answer added Suresh Venkat timeline score: 0
Dec 13, 2010 at 8:56 comment added Aaron Meyerowitz This is too cheap to qualify as more than a comment, but $p={\frac{1+\sqrt{5}}{2}}$ is the only case where $\ell^p$ is dual to $\ell^{p^2}$.
Dec 13, 2010 at 8:47 answer added Andreas Thom timeline score: 6
Dec 13, 2010 at 8:38 answer added Denis Serre timeline score: 5
Dec 13, 2010 at 8:17 answer added Piero D'Ancona timeline score: 2
Dec 13, 2010 at 6:53 answer added Andrey Rekalo timeline score: 12
Dec 13, 2010 at 6:40 history asked David Feldman CC BY-SA 2.5