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Dec 18, 2010 at 16:50 history edited George Lowther CC BY-SA 2.5
updated the explanation
Dec 14, 2010 at 1:33 history edited George Lowther CC BY-SA 2.5
typos
Dec 14, 2010 at 1:28 history edited George Lowther CC BY-SA 2.5
more explanation
Dec 14, 2010 at 1:05 comment added George Lowther Updated. I think it should all work now.
Dec 14, 2010 at 1:04 history edited George Lowther CC BY-SA 2.5
major reworking
Dec 13, 2010 at 13:10 comment added George Lowther Ok, I see how this can be fixed by dropping the condition $z^2=z$ and using a different property (P) - replacing it by a more intuitive (but still slightly messy) condition. I'll update this, tonight if I get time.
Dec 13, 2010 at 6:04 comment added George Lowther The mistake is in (1). Forcing $z^2=z$ means that property (P) cannot be satisfied
Dec 13, 2010 at 5:55 comment added George Lowther There's still an error here somewhere, because it can't work if z is chosen to be an idempotent. Oh well...
Dec 13, 2010 at 4:43 comment added George Lowther I don't have time to further work on this answer right now, so I'll leave the following note. As the z term is an idempotent, it can be removed from most of the construction and only added in at the last step. This should make it a bit simpler, and property (P) can be simplified.
Dec 13, 2010 at 4:13 history edited George Lowther CC BY-SA 2.5
Major reworking
Dec 12, 2010 at 22:21 history edited George Lowther CC BY-SA 2.5
clean up. point out error
Dec 12, 2010 at 17:48 history answered George Lowther CC BY-SA 2.5