Timeline for If $\Omega_{X/Y}$ is locally free of rank $\mathrm{dim}\left(X\right)-\mathrm{dim}\left(Y\right)$, is $X\rightarrow Y$ smooth?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| S Nov 19, 2018 at 23:47 | history | suggested | user86028 | CC BY-SA 4.0 |
LaTeXified
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| Nov 19, 2018 at 22:33 | review | Suggested edits | |||
| S Nov 19, 2018 at 23:47 | |||||
| Oct 1, 2009 at 21:14 | comment | added | Anton Geraschenko | @Jonathan: Oh, right, you could have the inclusion of an irreducible component. Good point. | |
| Oct 1, 2009 at 16:49 | comment | added | Jonathan Wise | A closed immersion doesn't have to have negative relative dimension. | |
| Oct 1, 2009 at 14:35 | comment | added | Anton Geraschenko | Thanks for the correction. I think that a closed immersion gives the same sort of counterexample as k[e]/(e^2) in characteristic 2. The relative sheaf of differentials is free, but of rank 0, rather than dim(X)-dim(Y), which is negative. | |
| Oct 1, 2009 at 5:43 | history | edited | Jonathan Wise | CC BY-SA 2.5 |
added 46 characters in body
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| Oct 1, 2009 at 4:49 | history | answered | Jonathan Wise | CC BY-SA 2.5 |