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Dec 10, 2010 at 22:47 comment added George Lowther Alternatively, let $B(t)$ be a 2d Brownian motion. $T_0$ = 0 and $T_{n+1}$ is the first time after $T_n$ that $\Vert B(t)-B(T_n)\Vert=1$. Then, $B(T_n)$ has the same dynamics as $A_n$ described above. As 2D Brownian motion is recurrent, this shows that $A_n$ is recurrent.
Dec 10, 2010 at 22:42 comment added George Lowther Yes, this definitely shows that it will sweep the plane.
Dec 10, 2010 at 22:39 history edited George Lowther CC BY-SA 2.5
typos: sphere->circle. spelling.
Dec 10, 2010 at 21:00 comment added Hugh J @Joesph : yes, circle.
Dec 10, 2010 at 20:43 comment added Joseph O'Rourke @Hugh: By "sphere" do you mean "circle"?
Dec 10, 2010 at 20:18 history answered Hugh J CC BY-SA 2.5