Timeline for Can the I-fold direct product be free?
Current License: CC BY-SA 2.5
13 events
| when toggle format | what | by | license | comment | |
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| Jun 16, 2011 at 4:12 | history | rollback | wxu |
Rollback to Revision 1
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| Dec 20, 2010 at 13:36 | history | edited | wxu | CC BY-SA 2.5 |
added 344 characters in body
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| Dec 16, 2010 at 0:40 | vote | accept | wxu | ||
| Dec 16, 2010 at 0:40 | vote | accept | wxu | ||
| Dec 16, 2010 at 0:40 | |||||
| Dec 16, 2010 at 0:39 | vote | accept | wxu | ||
| Dec 16, 2010 at 0:40 | |||||
| Dec 14, 2010 at 19:39 | answer | added | Tom Goodwillie | timeline score: 11 | |
| Dec 11, 2010 at 0:53 | vote | accept | wxu | ||
| Dec 16, 2010 at 0:39 | |||||
| Dec 10, 2010 at 14:36 | vote | accept | wxu | ||
| Dec 10, 2010 at 14:37 | |||||
| Dec 10, 2010 at 14:22 | comment | added | Tom Goodwillie | Every $\mathbb Z/p^k\mathbb Z$-module is a direct sum of cyclic modules: The fact that for this ring a free module is injective allows you to split any module as $F\oplus T$ where $F$ is free and $T$ is killed by $p^{k-1}$. Induct on $k$. | |
| Dec 10, 2010 at 11:03 | answer | added | ndkrempel | timeline score: 0 | |
| Dec 10, 2010 at 10:02 | answer | added | Torsten Ekedahl | timeline score: 8 | |
| Dec 10, 2010 at 9:49 | comment | added | Martin Brandenburg | Can you sketch the proof for $\mathbb{Z}/m$? We may reduce to a prime power. | |
| Dec 10, 2010 at 8:58 | history | asked | wxu | CC BY-SA 2.5 |