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Nov 10, 2009 at 16:28 comment added Jason Dyer Ah yes, they switch from proof to conjecture for the upper bound once they get to pentagons.
Nov 10, 2009 at 16:26 history edited Jason Dyer CC BY-SA 2.5
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Nov 10, 2009 at 16:21 comment added Philipp Lampe I doubt that the problem is solved over there. They prove that the area of the midpoint pentagon is equal to P/2 plus one fourth of the area of the star pentagon. But for the area of the star polygon they count the area of the middle pentagon twice (for some strange reason). In my opinion the arguments presented in the link show the equivalence between the two formulations of the problem given by Manuel.
Nov 10, 2009 at 16:15 history answered Jason Dyer CC BY-SA 2.5