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Dec 12, 2010 at 15:13 comment added Hans-Peter Stricker What are the real rational integers? Googling (google.com/search?q="real+rational+integers") didn't reveal a lot.
Dec 10, 2010 at 19:04 comment added Nick S For me a more natural candidate would be the $A^3$, where $A$ is the set of real rational integers. Otherwise, you would end up with certain standard curves (which physisist are interested) only having finitely many points. The question is then: what is arclenght or area and how do you calculate it?
Dec 10, 2010 at 13:15 answer added sleepless in beantown timeline score: 1
Dec 10, 2010 at 7:53 comment added Hans-Peter Stricker That's a good point, thank you! (Nevertheless, in principle it might be the case, that physical space is locally isomorphic to $\mathbb{Q}^3$, isn't it? But we just could not - by finitary means - distinguish it from $\mathbb{R}^3$?)
Dec 10, 2010 at 7:10 comment added S. Carnahan The reasons that physicists tend to give for considering discrete models of spacetime also eliminate metric spaces like $\mathbb{Q}^3$ from consideration. In particular, path integration seems to be significantly harder to axiomatize in your model than in the traditional picture.
Dec 9, 2010 at 12:33 answer added user2529 timeline score: 6
Dec 9, 2010 at 11:57 history edited Hans-Peter Stricker CC BY-SA 2.5
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Dec 9, 2010 at 9:13 history asked Hans-Peter Stricker CC BY-SA 2.5