Timeline for How to calculate Tor(R/I, R/J) ??
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 9, 2010 at 9:05 | comment | added | Martin Brandenburg | $I+J = R \Rightarrow I \cap J = IJ$ is an easy exercise in the beginning of commutative algebra and does not involve any Tor-functors. | |
| Dec 9, 2010 at 6:57 | comment | added | Angelo | "I think you don't understand what I asked" is not the most polite way to put it. | |
| Dec 9, 2010 at 3:16 | comment | added | Kripton | yes, that I know since the basic. lolol What I don't know is to prove that indirectly, I mean, using the fact that Tor(R/I,R/J)=(I∩J)/IJ. I must prove that tor vanishes to conclude that I∩J = IJ, see? | |
| Dec 9, 2010 at 2:25 | comment | added | Kripton | Thank you very much for your help. It was very useful. Concerning to 2), I think you don't understand what I asked. I need to prove that (I∩J) = IJ, using that Tor1(R/I,R/J)=(I∩J)/IJ and the fact that R=I+J. So I think if we prove that Tor vanishes in this case, we have the problem solved. Once again thank you. | |
| Dec 9, 2010 at 2:16 | vote | accept | Kripton | ||
| Dec 9, 2010 at 2:13 | vote | accept | Kripton | ||
| Dec 9, 2010 at 2:16 | |||||
| Dec 9, 2010 at 0:32 | history | answered | Steven Landsburg | CC BY-SA 2.5 |