J) ??

11 events

when toggle format	what		by	license	comment
Apr 28, 2012 at 20:55	answer	added	Hans Schoutens		timeline score: 8
Dec 9, 2010 at 3:10	comment	added	Kripton		yes, I've already proved the first part, but now I can't see the second. Anyway thank you for your comment.
Dec 9, 2010 at 3:01	comment	added	Steve D		I answered this a few days ago here: answers.yahoo.com/question/…
Dec 9, 2010 at 2:33	comment	added	Kripton		Karl, thank you for the answer. It with the one below allowed me to have the solution. I really apreciate that.
Dec 9, 2010 at 2:16	vote	accept	Kripton
Dec 9, 2010 at 2:13	vote	accept	Kripton
Dec 9, 2010 at 2:16
Dec 9, 2010 at 0:32	answer	added	Steven Landsburg		timeline score: 4
Dec 9, 2010 at 0:31	history	edited	Karl Schwede	CC BY-SA 2.5	Fixed latex typo
Dec 9, 2010 at 0:06	comment	added	Kripton		I mean Tor_1 over the ring R. That is exactly what I did, but I get Tor(R/I x R/J) = Ker(I x R/I ----> A x A/J), where x is the tensor product, but then I don't know how to prove the equality.
Dec 8, 2010 at 23:58	comment	added	Charles Rezk		Your question is ambiguous: which Tor group do you mean? In any case, it really does sound like homework to me. Here's a hint: think about what happens if you apply Tor to an exact sequence like $0\to I\to R\to R/I\to 0$.
Dec 8, 2010 at 23:48	history	asked	Kripton	CC BY-SA 2.5