Timeline for Hom functor and Cohen-Macaulay modules
Current License: CC BY-SA 4.0
2 events
| when toggle format | what | by | license | comment | |
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| 3 hours ago | comment | added | Jason Starr | No, that is not true. Let $A$ be $\mathbb{C}[[s,t]/\langle st \rangle$, let $M$ be $A/\langle s \rangle$, and let $N$ be $A/\langle t \rangle$. Then $\text{Hom}_A(M,N)$ is the zero module. | |
| 5 hours ago | history | asked | Naga Venkata | CC BY-SA 4.0 |