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35 mins ago comment added Stefaan Vaes Most of the time, in particular when all $p_n$ are equal, the measure $\mu$ is nonatomic. But the support is indeed the entire Cantor set. If $U \subset (\mathbb{Z}/Z\mathbb{Z})^{\mathbb{N}}$ is an open subset, there exists an $n \in \mathbb{N}$ and $x_1,\ldots,x_n \in \mathbb{Z}/Z\mathbb{Z}$ such that $\{x_1\} \times \cdots \times \{x_n\} \times (\mathbb{Z}/Z\mathbb{Z})^{[n+1,\infty)}$ is a subset of $U$, with strictly positive measure $\mu_1(x_1) \cdots \mu_n(x_n)$.
9 hours ago vote accept Tomás Pacheco
10 hours ago comment added Tomás Pacheco What a neat example, thank you! Just to make sure I followed, if we pick different $\lambda$'s we obtain different probability measures, all of which give non-zero measure to points, meaning the support is always the whole Cantor set, correct?
yesterday history answered Stefaan Vaes CC BY-SA 4.0