Timeline for Question on gamma matrices
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| yesterday | answer | added | Bernd Ammann | timeline score: 1 | |
| Dec 12 at 14:54 | comment | added | Branimir Ćaćić | 1) The so-called Clifford action $\gamma$ is always taken to be bundle morphism, so that for each $p \in M$, $\gamma$ restricts to a linear map $\gamma_p : T_p(M) \to \operatorname{End}(S_p)$. 2) Your interpretation of $\nabla \gamma = 0$ is correct. In general, this is a condition you can look for in a connection on a spinor bundle, which makes it a Clifford connection. | |
| Dec 12 at 14:27 | history | edited | B.Hueber | CC BY-SA 4.0 |
deleted 12 characters in body
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| Dec 12 at 14:21 | history | asked | B.Hueber | CC BY-SA 4.0 |