Timeline for Second order differential equation with non constant coefficient
Current License: CC BY-SA 4.0
14 events
when toggle format | what | by | license | comment | |
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Dec 15 at 8:03 | vote | accept | trying | ||
Dec 13 at 16:47 | answer | added | Fred Hucht | timeline score: 3 | |
Dec 13 at 11:30 | comment | added | trying | @FredHucht Do you have any reference for this? Your explanation is a bit vague for me. | |
Dec 13 at 11:30 | comment | added | trying | @GeraldEdgar thanks i understand now. | |
Dec 13 at 8:04 | comment | added | Fred Hucht | @trying Ok, my comment remains correct. | |
Dec 13 at 6:58 | history | edited | trying | CC BY-SA 4.0 |
added 2 characters in body
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Dec 13 at 6:57 | comment | added | trying | @FredHucht sorry yes, I fixed the typo. | |
Dec 12 at 15:31 | comment | added | Fred Hucht | @trying Please check your 2nd equation, I think it should read $f(t)$ instead of $\sqrt{f(t)}$. Else, there is a factor $1/2$ missing in the first equation. | |
Dec 12 at 15:15 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
Minor Math Jaxing and formatting
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Dec 12 at 15:13 | comment | added | Fred Hucht |
The logarithmic derivative $f'(t)/f(t)$ suggests to consider $f(t)=\exp(a_0+a_1 t+a_2 t^2+a_3 t^3)$, which is solved by the tri-confluent Heun function(HeunT[] in Mathematica). Simpler cases (some $a_k=0$) give Hermite polynomials, Bessel functions (see comment by @GeraldEdgar), or simple exponentials.
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Dec 12 at 14:33 | review | Close votes | |||
yesterday | |||||
Dec 12 at 14:29 | comment | added | Gerald Edgar | If $f(t) = t^a$, then we get solution with Bessel functions... $$C_1t^{(1-a)/2} J_{(1-a)/2}(kt)+C_2t^{(1-a)/2} Y_{(1-a)/2}(kt)$$ | |
Dec 12 at 13:26 | history | edited | trying | CC BY-SA 4.0 |
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Dec 12 at 13:03 | history | asked | trying | CC BY-SA 4.0 |