Timeline for A representable functor that does not admit an adjoint? [closed]

14 events

when toggle format	what		by	license	comment
Dec 7 at 22:46	vote	accept	Yilmaz Caddesi
S Dec 6 at 2:00	history	migration rejected
S Dec 6 at 2:00	history	unlocked	CommunityBot
S Dec 4 at 18:27	history	migrated	მამუკა ჯიბლაძე Denis T Tyrone R. van Dobben de Bruyn abx		to math.stackexchange.com
S Dec 4 at 18:27	history	locked	CommunityBot
S Dec 4 at 18:27	history	closed	მამუკა ჯიბლაძე Denis T Tyrone R. van Dobben de Bruyn abx		Not suitable for this site
Dec 4 at 18:19	history	edited	Yilmaz Caddesi	CC BY-SA 4.0	deleted 4 characters in body
Dec 4 at 18:00	comment	added	John Palmieri		What does "simplest" mean?
Dec 4 at 17:34	review	Close votes
Dec 4 at 18:32
Dec 4 at 17:28	answer	added	Sridhar Ramesh		timeline score: 1
Dec 4 at 17:28	comment	added	Denis T		I'd say that there's even more obvious obstruction. Left adjoint preserves colimits, so it should send colimit of the empty diagram — the empty set — to the initial object of a category (or terminal object, depending on whether you take covariant or contravariant representable). So, for any category with two arrows and one object (for both of them, actually) the only Hom-functor you have is non-representable.
Dec 4 at 17:27	review	Low quality posts
Dec 4 at 18:32
Dec 4 at 17:18	comment	added	მამუკა ჯიბლაძე		The left adjoint to $\hom(A,-)$ has to send a set $S$ to the coproduct of $S$ copies of $A$. This question would be more suitable on math.SE though
Dec 4 at 17:06	history	asked	Yilmaz Caddesi	CC BY-SA 4.0