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Timeline for Connectedness of degeneracy loci

Current License: CC BY-SA 4.0

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Dec 6 at 11:23 answer added Jason Starr timeline score: 0
Dec 5 at 21:06 answer added Cob timeline score: 3
Dec 5 at 10:37 comment added Enrico In general, you should be aware of relaxing these hypothesis too much. If you take $X=Gr(n,2n)$, $E= \mathcal{O}_G, F= Sym^2(U^*)$ (with $U$ the tautological bundle), you get a zero locus (in this case the only degeneracy loci) which has two connected components. In this case $ E^* \otimes F= Sym^2(U^*)$ is definitely globally generated, but I am not sure about its bigness.
Dec 4 at 23:45 comment added Jason Starr I suspect this can be proved using Minoccheri’s connectedness theorem. I will try to write it up as an answer soon.
Dec 4 at 17:14 comment added Cob @JasonStarr I am assuming that $E^* \otimes F$ is globally generated, hence yes, it is a quotient of $r$ copies of the structure sheaf ${\mathcal O}_X$. I am also assuming that $E^* \otimes F$ is big, in the sense that its tautological line bundle ${\mathcal O}(1)$ is big on ${\mathbb P}(E^* \otimes F)$. This implies that the determinant of $E^* \otimes F$ is big, hence the image of the associated morphism has dimension $n$, hence also the image of the morphism into the Grassmannian has dimension $n$. But, in general, it might not be birational.
Dec 4 at 17:03 comment added Cob @J. W. Tanner Thanks!
S Dec 4 at 16:57 history suggested J. W. Tanner CC BY-SA 4.0
I think I corrected spelling in title
Dec 4 at 16:38 comment added Jason Starr Do you assume that $E^*\otimes F$ is a quotient of a direct sum of a finite number (say $r$) of copies of the structure sheaf on a smooth, projective variety $X$? Do you assume that the induced morphism from $X$ to the Grassmannian $\text{Grass}(ef,r)$ is birational to its image?
Dec 4 at 16:17 review Suggested edits
S Dec 4 at 16:57
Dec 4 at 14:39 history asked Cob CC BY-SA 4.0