Timeline for Question about maps on cofibers being zero
Current License: CC BY-SA 4.0
3 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Nov 30 at 5:51 | history | edited | Tim Campion | CC BY-SA 4.0 |
added 70 characters in body
|
Nov 30 at 5:47 | comment | added | Tim Campion | I feel the need to put in a reminder that if we look at $Spectra$ instead of $D(\mathbb Z)$, then we should note that $p = 0$ on $\mathbb S / p$ iff $p$ is odd. On $\mathbb S / 2$ we have $4 = 0$ but $2 \neq 0$. This is related to the fact that $\mathbb S / 2$ does not admit a unital multiplication. In general in a symmetric monoidal stable category with unit $S$, if $\phi : \Sigma^n S \to S$ is an endomorphism-up-to-shift, then $\phi^2 = 0$ on $S / \phi$, but it's often the case that $\phi \neq 0$ on $S / \phi$. | |
Nov 30 at 5:43 | history | answered | Tim Campion | CC BY-SA 4.0 |