Timeline for An inequality that may be of isoperimetric nature
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Nov 22 at 19:26 | vote | accept | Raz Kupferman | ||
| Nov 22 at 9:52 | history | became hot network question | |||
| Nov 22 at 4:20 | answer | added | Fedor Petrov | timeline score: 10 | |
| Nov 21 at 19:56 | comment | added | Aleksei Kulikov | @GiorgioMetafune you are absolutely right, it is indeed $L^1$-norm. I see how to get some constant with a bit of suffering, but not sure if I can get $1$... | |
| Nov 21 at 19:52 | comment | added | Giorgio Metafune | @AlekseiKulikov Not clear to me how you use Wirtinger. On the RHS you have an $L^1$-norm. I guess it is $f$, not $f'$. | |
| Nov 21 at 14:40 | comment | added | Aleksei Kulikov | @IosifPinelis Cauchy--Schwarz + Wirtinger's inequality, for example. | |
| Nov 21 at 14:27 | comment | added | Iosif Pinelis | "The inequality is easy to show if the $4\pi$ on the left-hand side is replaced by $1$." -- How is this done? | |
| Nov 21 at 13:54 | comment | added | Aleksei Kulikov | Do you perhaps want to have $f'^2$ on the right instead of $f^2$? | |
| Nov 21 at 13:53 | history | edited | YCor |
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| Nov 21 at 13:46 | history | asked | Raz Kupferman | CC BY-SA 4.0 |