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Nov 23 at 13:18 answer added Alexandre Eremenko timeline score: 2
Nov 19 at 0:13 comment added Gabriel Franceschi Libardi Let us continue this discussion in chat.
Nov 18 at 22:28 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 21:04 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 21:02 comment added Gabriel Franceschi Libardi Now I see that $\xi$ always exists given the other priors. I was thinking of proving the existence of $\xi$ and then applying a density argument: some sufficiently smooth $\eta$ should exist as close as we want from $\xi$ (with the same endpoints, of course).
Nov 18 at 20:59 comment added Pietro Majer I think the answer to the Problem is yes (in both versions), and you don’t need to assume the existence of $\xi$. There is a nbd of the curve $\gamma$ which is foliated by $C^k$ curves; you can cut these curves with the normal at the enpoints of $\gamma$ (the resulting picture looks like a maccherone). Then you can connect $\gamma$ and one of these close curves by a small curve on both sides, and obtain a close simple curve.
Nov 18 at 20:37 comment added Pietro Majer If $\Gamma\subset \mathbb R^2$ is a $C^1$ regular simple closed curve (the image of a $C^1$ injective $\gamma:\mathbb S^1\to\mathbb R^2$ with $\dot\gamma(t)\neq0 \;\forall t$), I think, the set of all straight lines $\ell$ that have infinitely many intersections with $\Gamma$ is at most countable.
Nov 18 at 20:15 comment added Gabriel Franceschi Libardi Great! I did not mean to ask about the "motivating problem" on this post, maybe my discussion of it is too detailed. Should I make it more brief?
Nov 18 at 20:06 comment added Pietro Majer ops, my comment above has been made obscure by the auto-correct. I just meant that the question in the Motivation may be easier than the subsequent problems (as a side note: it should be better to ask one question per post)
Nov 18 at 19:58 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 19:50 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 19:45 comment added Gabriel Franceschi Libardi I heavily revised my question, I hope it is clearer now. @Pietro, could you please specify which priors in my question are unnecessary? They would all be necessary as far as I understand.
Nov 18 at 19:21 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 16:18 comment added Pietro Majer All problems are doable, but it think to answer the question in the motivation you don't need the constrictions in the subsequeent problems.
Nov 18 at 14:53 history edited Gabriel Franceschi Libardi CC BY-SA 4.0
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Nov 18 at 14:40 comment added Gabriel Franceschi Libardi Thank you for pointing that out @Alexandre, I will clarify that. In the motivating problem, it would be interesting to come up with smooth paths ($\gamma'(t)\neq 0$), and it is possible to construct a $C^1$-smooth path that has the desired property. Also, I just realized that the first part of my problem is trivial, it would suffice to concatenate $\gamma(t)$ with $\gamma(1 - t)$ if the resulting path is not required to be simple. It is the second part of the problem that is interesting, and it can be asked of many kinds of paths ($C^1$, $C^1$-smooth, etc).
Nov 18 at 13:42 history edited Iosif Pinelis
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Nov 18 at 12:29 comment added Alexandre Eremenko Please specify what you mean by "infinitely-differentiable path" in the original problem: there exists an infinitely differentiable parametrization $\gamma(t)$ or there exists such a parametrization with $\gamma'(t)\neq 0$?
S Nov 18 at 4:53 review First questions
Nov 18 at 5:37
S Nov 18 at 4:53 history asked Gabriel Franceschi Libardi CC BY-SA 4.0