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Nov 15 at 16:14 vote accept Darius
Nov 15 at 16:13 vote accept Darius
Nov 15 at 16:13
Nov 15 at 16:12 comment added Darius I actually wanted to ask if $\frac{J_m}{{2^m m!}}=O(m^p)$ but you already answered implicitly to my question. Thank you very much !
Nov 14 at 22:18 comment added Iosif Pinelis @CarloBeenakker : Thank you for your comment. This is now fixed.
Nov 14 at 22:18 history edited Iosif Pinelis CC BY-SA 4.0
added 9 characters in body
Nov 14 at 21:04 comment added Carlo Beenakker I think the factor $\pi^{1/2}$ in your $c_m$ should be $\tfrac{1}{2}\pi^{1/2}$, at least that is what I find; one way to check this, is to set $y=0$, when $J_m=\tfrac{1}{2}\pi^{1/2} 2^m m!$ exactly.
Nov 14 at 20:14 history answered Iosif Pinelis CC BY-SA 4.0