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Nov 11 at 19:07 history edited RobPratt CC BY-SA 4.0
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Nov 11 at 16:41 comment added Alexander Braverman I actually think that it is important that the form on E is skew-symmetric (but I might be wrong)
Nov 11 at 15:22 comment added Will Sawin To trivialize the determinant of $E$.
Nov 11 at 14:38 comment added Alexander Braverman Where exactly are you using the symplectic structure on E?
Nov 11 at 14:06 comment added Will Sawin Take a cell decomposition of $X$ which gives a chain complex computing the cohomology of $E$. The alternating product of determinants of this chain complex is the same before and after you take cohomology, and is a power of $\det(E)$, so can be trivialized by the canonical trivialization of $\det(E)$. Maybe this one works?
Nov 11 at 13:57 history edited Alexander Braverman CC BY-SA 4.0
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Nov 11 at 13:38 history asked Alexander Braverman CC BY-SA 4.0