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Nov 10 at 17:33 comment added Jakobian Thank you, inspired by this answer I've shown that for any locally compact Hausdorff scattered space $Y$ there exists a space $X$ with only zero-dimensional compactifications and $\beta X\setminus X\cong Y$. Moreover, whenever $X$ is a strongly zero-dimensional space and $\beta X\setminus X$ is locally compact, then having only zero-dimensional compactifiactions is equivalent to $\beta X\setminus X$ being scattered.
Nov 9 at 19:09 vote accept Jakobian
Nov 9 at 15:26 history answered KP Hart CC BY-SA 4.0