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S Nov 17 at 23:00 history bounty ended CommunityBot
S Nov 17 at 23:00 history notice removed CommunityBot
S Nov 9 at 21:37 history bounty started lasik43
S Nov 9 at 21:37 history notice added lasik43 Draw attention
Nov 8 at 10:21 history edited lasik43 CC BY-SA 4.0
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Nov 8 at 10:20 comment added lasik43 @ChristianRemling If $h(x) = x$, then the RHS operator is trace class, see e.g. Barry Simon: Trace ideals, Theorem 4.5. For general $h$, I think we might need continuously differentiable (and obviously $h(0) = 0$); I updated the question.
Nov 7 at 22:41 comment added Christian Remling Is it even clear that the operator on the RHS (for $h(x)=x$) is compact?
Nov 7 at 19:39 history edited lasik43 CC BY-SA 4.0
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S Nov 7 at 19:30 review First questions
Nov 7 at 20:21
S Nov 7 at 19:30 history asked lasik43 CC BY-SA 4.0