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Nov 5 at 13:56 comment added Simon Henry Oh I see, that make sense too.
Nov 4 at 22:27 comment added Zhen Lin I think $\mathbb{E}'$ is supposed to be $\mathbb{F}\textrm{am} (\mathbb{E})$, so the fibre over $1$ is the total category $\mathbb{E}$ etc.
Nov 4 at 20:00 comment added Simon Henry Should $\mathbb{E}'$ be $\mathbb{E}^X$, defined by the fact that its fiber over $I$ is the fiber over $I \times X$ for $\mathbb{E}$ (for $X$ some fixed object of the topos)
Nov 4 at 19:57 comment added Simon Henry That is very interesting, I need to think about it a little more, but that does look promising.
Nov 4 at 18:49 history answered Jem CC BY-SA 4.0