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Oct 28 at 4:12 comment added Nate River In any case, if random dynamical systems are of interest at all, I can’t imagine that their ergodic properties would not be of interest.
Oct 28 at 4:08 comment added Nate River I think at least ergodicity of random transformations is interesting in the context of “card shuffling”, or in general trying to uniformly mix a space with random operations…
Oct 28 at 4:06 comment added Nate River @Anthony Quas Only one way to find out 😁
Oct 28 at 4:02 comment added Anthony Quas I would say the definitions are good definitions if they lead to interesting behaviour. For a regular system, ergodicity is interesting, because, for example, the conclusion of Birkhoff's theorem is particularly nice. The regular definition of weak-mixing is nice because it relates to eigenvalues, and can be leveraged to prove theorems such as Furstenberg/Szemerédi's theorem about arithmetic progressions in dense subsets of the integers. It may be that the random versions are similarly consequential. Or it may not...
Oct 27 at 17:59 comment added Nate River I am not too familiar with the formal theory of random dynamical systems, but asking for ergodic/mixing properties of the random system feels rather natural no? @AnthonyQuas
Oct 27 at 14:09 comment added Anthony Quas I guess I’m wondering whether the notion of “weak mixing for a random composition of maps” has been defined elsewhere, and whether it has proved to be useful.
Oct 27 at 4:40 comment added Nate River So for every choice of $\omega$, you get a fixed sequence of transformation and we ask if this is weak mixing almost surely wrt $\omega$. Will Sawin's answer shows in fact it's almost surely not weak mixing! @AnthonyQuas
Oct 27 at 4:38 comment added Anthony Quas I would have asked what you meant by weak-mixing. It's normally defined for a fixed transformation, when it is equivalent to the non-existence of non-constant eigenfunctions. Did you mean the condition that Will Sawin showed does not hold in his answer? (this seems the most reasonable guess). Maybe it would make more sense to define the random rotation as a skew product $T\colon [0,1)^\mathbb Z\times [0,1)\to [0,1)^\mathbb Z\times [0,1)$ that is $T(\omega,t)=(\sigma(\omega),t+\omega_0\bmod1)$.
Oct 26 at 16:23 history became hot network question
Oct 26 at 12:03 vote accept Nate River
Oct 26 at 11:24 vote accept Nate River
Oct 26 at 11:47
Oct 26 at 11:22 vote accept Nate River
Oct 26 at 11:23
Oct 26 at 11:13 answer added Will Sawin timeline score: 7
Oct 26 at 9:10 comment added Nate River If you take $[0, 1]^{\mathbb N}$ as a model for the probability space, then the natural measure is the countable product of the uniform measure, and almost surely means with respect to this.
Oct 26 at 9:07 comment added Nate River Note that this is a different $[0, 1]$ than the underlying space of the dynamics.
Oct 26 at 9:06 comment added Nate River I mean almost surely with respect to the probability space underlying the independent random variables $Z_i$. @AlessandroDellaCorte
Oct 26 at 8:48 comment added Alessandro Della Corte What do you mean by "almost surely" on $[0,1]^{\mathbb{N}}$?
Oct 26 at 8:37 history edited Nate River CC BY-SA 4.0
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Oct 26 at 8:22 history asked Nate River CC BY-SA 4.0