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Oct 30 at 17:49 history edited R. Chen CC BY-SA 4.0
added 74 characters in body
Oct 26 at 18:23 answer added Friedrich Knop timeline score: 4
Oct 25 at 19:47 comment added LSpice Surely you don't mean that the horospherical subgroup is characterised by $N_G(S) = P^-$? This condition is also satisfied by $S = P^-$ itself. A quick skim suggests that you also want $S \cap B = B_0$, in the notation of Korollar 2.4 (which I can't understand since my German is very poor—I guess a Borel and a generic stabiliser?). (By the way, Markdown has its own syntax for italics, which works better than faking it through MathJax: compare horospherical type *horospherical type* to $\textit{horospherical type}$ $\textit{horospherical type}$. I edited accordingly.)
Oct 25 at 19:44 history edited LSpice CC BY-SA 4.0
Titles of references
Oct 25 at 14:21 history edited YCor
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Oct 25 at 14:06 history asked R. Chen CC BY-SA 4.0