Skip to main content
4 events
when toggle format what by license comment
Oct 19 at 20:51 comment added Mohsen Shahriari @MohammadTahmasbi You're welcome. Indeed, if you're familiar with models in which the "classical reals" $ \mathbb R ^ { \text e } $ are not isomorphic to the "bounded extended reals" $ \mathbb R ^ { \text {be} } $ (also called McNeil reals), you can find there asymptomatically regular sequences of classical reals that are not convergent (and thus not Cauchy either).
Oct 19 at 2:52 comment added Mohammad Tahmasbi Nice answer. It solves the problem. We can't show that $(b_n)$ is a Cauchy sequence (regardless of having a modulus) using weak Archimedean property instead of Archimedean property. Thanks.
Oct 19 at 2:34 vote accept Mohammad Tahmasbi
Oct 18 at 15:22 history answered Mohsen Shahriari CC BY-SA 4.0