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Oct 15 at 14:03 comment added Vít Tuček I think there will be cases where $\|Xv\| = \|Yv\|$ even though $\alpha$ and $\beta$ are incomparable.
S Oct 15 at 13:32 review First questions
Oct 15 at 18:30
S Oct 15 at 13:32 history asked d'Alembert CC BY-SA 4.0