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Dec 2, 2010 at 18:44 comment added Greg Muller I had missed the requirement that $B$ was a ring, rather than an $A$-module. Of course, I can replace $B$ by its symmetric tensor algebra to get a ring which is faithful but not flat.
Dec 2, 2010 at 18:09 vote accept Ketil Tveiten
Dec 2, 2010 at 17:57 comment added Karl Schwede @Greg, do you know of any examples of commutative rings $B$ with unity?
Dec 2, 2010 at 17:41 comment added Achilleas K Yes. I have now replaced "faithfully flat" to "faithful" in my answer.
Dec 2, 2010 at 17:37 history edited Achilleas K CC BY-SA 2.5
deleted 7 characters in body; added 2 characters in body
Dec 2, 2010 at 17:29 comment added Greg Muller Yes, it is possible to be faithful without being flat. Let $A=k[x,y]$ and let $B= xA+yA$.
Dec 2, 2010 at 15:55 comment added Graham Leuschke Why must $B$ be flat? Seems like this is the content of the earlier question -- is it possible for $-\otimes_AB$ to be faithful without $B$ being flat.
Dec 2, 2010 at 15:52 vote accept Ketil Tveiten
Dec 2, 2010 at 18:09
Dec 2, 2010 at 14:41 history answered Achilleas K CC BY-SA 2.5