Timeline for If a semigroup embeds into a group, then is it a subdirect product of groups?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Oct 9 at 16:21 | comment | added | Salvo Tringali | I posted an answer: mathoverflow.net/questions/480364#480364 I hope I haven't overlooked anything irreparable. | |
| Oct 9 at 15:51 | comment | added | Benjamin Steinberg | I thought about this example for your question. Both examples have a unique minimal group congruence. I'm not sure whether either answer your first question. I ran into this example a few days ago thinking about that question. Notice trotters example has the property that any cancellative quotient that has an idempotent is a group do it should have to be a subdirect product of cancellative semigroups without idempotents. | |
| Oct 9 at 12:14 | comment | added | Salvo Tringali | Thanks for the reference (and +1). I'm accepting YCor's answer because (i) it came first and (ii) I believe his construction can be used to give a negative answer to mathoverflow.net/questions/480202 | |
| Oct 9 at 1:51 | history | answered | Benjamin Steinberg | CC BY-SA 4.0 |