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Feb 7, 2021 at 4:17 comment added R. van Dobben de Bruyn Similar to 1: a subset of a group that is closed under multiplication and inversion is a subgroup.
Dec 4, 2010 at 22:46 comment added Zsbán Ambrus Isn't the more right statement that a transitive and irreflexive relation is assymetric?
Dec 2, 2010 at 15:21 comment added Nate Eldredge +1 for #2. Baby Rudin is another offender. And many authors use so-called "diagonalization tricks" for proving compactness theorems like Arzela-Ascoli and Prohorov, which typically reduce to the compactness of $[0,1]^\mathbb{N}$.
Dec 2, 2010 at 15:13 comment added Nate Eldredge For big-list questions, it's usually best to post independent answers as separate answers.
Dec 2, 2010 at 9:18 history answered safak CC BY-SA 2.5