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Oct 12 at 3:05 review Close votes
Oct 13 at 3:08
Oct 6 at 9:48 vote accept mattTheMathLearner
Oct 5 at 20:43 answer added Carlo Beenakker timeline score: 7
S Oct 5 at 17:55 history suggested CommunityBot CC BY-SA 4.0
\operatorname in the subject line
Oct 5 at 17:31 review Suggested edits
S Oct 5 at 17:55
Oct 5 at 17:10 history edited LSpice CC BY-SA 4.0
`\operatorname`; deleted "Thank you"
Oct 5 at 16:39 comment added Carlo Beenakker crossposted at math.stackexchange.com/q/4980499/87355 --- it does not seem a trivial question, perhaps keep it open?
Oct 5 at 16:15 history edited mattTheMathLearner CC BY-SA 4.0
added 29 characters in body
Oct 5 at 16:14 comment added mattTheMathLearner the integrand is continuous, correct. I meant that the indefinite integral has a discontinuity.
Oct 5 at 15:42 comment added Carlo Beenakker the integrand does not have a singularity, it is continuous on $0<x<10$
Oct 5 at 13:45 review Close votes
Oct 7 at 10:20
S Oct 5 at 13:22 review First questions
Oct 5 at 17:58
S Oct 5 at 13:22 history asked mattTheMathLearner CC BY-SA 4.0