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Oct 2 at 13:34 vote accept Arkadi Predtetchinski
Oct 1 at 18:48 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 1 at 18:29 comment added Arkadi Predtetchinski You are right: I meant f real-valued non-negative. The upper bound on the integral is particularly helpful.
Oct 1 at 18:03 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 1 at 17:50 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 1 at 17:49 comment added Iosif Pinelis @AlekseiKulikov : The case $f\ge0$, too, has now been (partially) considered.
Oct 1 at 17:39 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 1 at 17:34 history edited Iosif Pinelis CC BY-SA 4.0
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Oct 1 at 17:08 comment added Iosif Pinelis @AlekseiKulikov : This is what I suspected. On the other hand, I see "real-valued".
Oct 1 at 17:04 comment added Aleksei Kulikov While this answer is technically correct, I am willing to bet that Arkadi had in mind that $f$ must be non-negative...
Oct 1 at 16:54 history answered Iosif Pinelis CC BY-SA 4.0