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LSpice
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For studying symmetries of certain PDEs, it would be convenient if a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$$\phi : G\to \mathbb{Z}_2 = \{-1, 1\}$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

For studying symmetries of certain PDEs, it would be convenient if a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

For studying symmetries of certain PDEs, it would be convenient if a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2 = \{-1, 1\}$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

edited body; edited title
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Quoka
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Existence of a group $G\subset O(n)$ along with anda homomorphism on $\mathbb$\phi :G \to \mathbb{RZ}^N$_2 = \{-1,1\}$ with some properties

For studying symmetries of certain PDEs, it would be convenient isif a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

Existence of a group with and homomorphism on $\mathbb{R}^N$ with some properties

For studying symmetries of certain PDEs, it would be convenient is a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

Existence of a group $G\subset O(n)$ along with a homomorphism $\phi :G \to \mathbb{Z}_2 = \{-1,1\}$ with some properties

For studying symmetries of certain PDEs, it would be convenient if a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

added 14 characters in body
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Quoka
  • 185
  • 8

For studying symmetries of certain PDEs, it would be convenient is a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$, is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

For studying symmetries of certain PDEs, it would be convenient is a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$,
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

For studying symmetries of certain PDEs, it would be convenient is a certain type of group existed.

I am looking for a closed subgroup $G$ of the the orthogonal group $O(n)$ along with a continuous homomorphism $\phi : G\to \mathbb{Z}_2$ such that

  1. If $x\in\mathbb{R}^n,\, x\ne 0$ then $\operatorname{dim}(Gx) > 0$.
  2. $\phi : G\to \mathbb{Z}_2$ is surjective.
  3. There exists $x\in \mathbb{R^n}$ such that $\{g\in G : gx = x\}\subseteq \operatorname{ker}\phi$.

I get the feeling such a group does not exist. As I am not great with groups/geometry, I was hoping someone could help lead me in the right direction (or direct me towards appropriate references).

Source Link
Quoka
  • 185
  • 8
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