Skip to main content
7 events
when toggle format what by license comment
Sep 26 at 5:10 comment added Zuhair Al-Johar @JasonStarr, yes, to have my original intention I must forbid this joint action of any finite number of axioms to go against $V \neq L$, like adding that any finite conjunction of axioms of $\sf T$ is an axiom of $\sf T$ also. But that would be messy.
Sep 25 at 23:04 comment added Jason Starr I get it now. Results that are separately consistent with $V\neq L$ need not be jointly consistent with $V\neq L$.
Sep 25 at 21:55 comment added Joel David Hamkins My two axioms have that feature. And yet jointly they imply V=L.
Sep 25 at 21:06 comment added Jason Starr I think the poster only wants to add consequences of $V=L$ that are also consistent with $V\neq L$.
Sep 25 at 17:11 vote accept Zuhair Al-Johar
Sep 25 at 16:08 history edited Joel David Hamkins CC BY-SA 4.0
added 53 characters in body
Sep 25 at 15:48 history answered Joel David Hamkins CC BY-SA 4.0