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Sep 23 at 7:49 history bounty ended Fabius Wiesner
Sep 19 at 17:29 history edited Alex Ravsky CC BY-SA 4.0
edited body
Sep 19 at 14:08 comment added Fabius Wiesner Thank you very much! I think $k\to (A_1'\cup B'_k,A_1'\cup B'_k)$ should be $k\to (A_1'\cup B'_k,A_2'\cup B'_k)$ (I cannot edit just one character).
Sep 19 at 13:45 history edited Alex Ravsky CC BY-SA 4.0
added 8 characters in body
Sep 19 at 13:31 history answered Alex Ravsky CC BY-SA 4.0