Timeline for Growth of the hyperexponential
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Sep 19 at 17:09 | answer | added | nombre | timeline score: 1 | |
| Sep 19 at 16:39 | history | edited | nombre | CC BY-SA 4.0 |
added 6 characters in body
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| Sep 19 at 16:36 | comment | added | nombre | I edited accordingly. The two definitions are equivalent. For math text, the syntax is latex, and you have to put things between dollar signs. E.g. \log_n between two dollar signs is $\log_n$. | |
| Sep 19 at 16:35 | comment | added | Noah Schweber | @user23467 Use mathjax. | |
| Sep 19 at 16:34 | history | edited | nombre | CC BY-SA 4.0 |
specifying OP's question
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| Sep 19 at 16:33 | comment | added | user23467 | How do you get that math text? | |
| Sep 19 at 16:24 | comment | added | user23467 | The one I saw had an E, and it was defined as exp_n (2^-k log_n(a)) <= b <= exp_n (k log_n(a)) | |
| Sep 19 at 12:05 | comment | added | nombre | Hi there, I'm probably best suited to answer your question, but I'm not sure what you mean by "an equivalence of <>E". Are you perhaps using notations from an article where you read about this? If so, this will be difficult to read by people here since these notions are niche and hardly consensual. The equivalence relation you seem to be alluding to is Berarducci and Mantova's relation $\asymp_L$ on positive infinite surreal numbers, where $a \asymp_L b \Leftrightarrow \exists n \in \mathbb{N}, |\log_n(a) -\log_n(b)|\leqslant 1$, $\log_n$ being the $n$-fold iterate of $\log$. | |
| Sep 19 at 8:12 | review | Close votes | |||
| Oct 7 at 3:07 | |||||
| S Sep 19 at 7:47 | review | First questions | |||
| Sep 19 at 7:56 | |||||
| S Sep 19 at 7:47 | history | asked | user23467 | CC BY-SA 4.0 |