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Sep 12 at 20:59 comment added Pietro Majer Sorry I don't understand: in particular for $y=0\in G$, doesn't this say $f(\phi(x))=1$ for all $x$, so $f$ is constant?
S Sep 12 at 18:26 review First questions
Sep 12 at 19:44
S Sep 12 at 18:26 history asked Chandler Halderson CC BY-SA 4.0