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Sep 12 at 17:00 vote accept Daniel Pomerleano
Sep 12 at 13:11 comment added Oscar Randal-Williams @DrewHeard: I don't think that matters, because the multiplication on $E^*(BU(n))$ happens to be commutative, and everything else is only considered as a left module over that.
Sep 12 at 12:23 comment added Drew Heard I was also worried about the multiplicative nature of the spectral sequence: it doens't cause problems that (at p = 2) K(n) does not admit a homotopy commutative ring structure?
Sep 12 at 9:04 history answered Oscar Randal-Williams CC BY-SA 4.0