Skip to main content
Became Hot Network Question
removed capitals from title
Link
YCor
  • 63.9k
  • 5
  • 187
  • 286

Adjoints to Changechange of Basebase Functors

I additionally asked if the answer to question would follow from the composition of adjunctions.
Source Link
Siya
  • 615
  • 1
  • 7

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/E \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true? Is this just using the composition of adjunctions?

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/E \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true?

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/E \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true? Is this just using the composition of adjunctions?

edited body
Source Link
Siya
  • 615
  • 1
  • 7

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/B \to \mathbf{Cat}$$d^*\colon \mathbf{Cat}/E \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true?

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/B \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true?

Consider a functor $p \colon E \to B$ in $\mathbf{Cat}$. Then there is an induced functor $p^* \colon \mathbf{Cat}/B \to \mathbf{Cat}/E$. It is on objects given by

enter image description here

But now I wanna ask its possible to investigate using the domain functor $d^*\colon \mathbf{Cat}/E \to \mathbf{Cat}$ that to say that $p^*$ has a right adjoint is equivalent to saying that the functor $- \times_B E \colon \mathbf{Cat}/B \to \mathbf{Cat}$ has a right adjoint. Is this true?

Source Link
Siya
  • 615
  • 1
  • 7
Loading