Timeline for Splitting in triangulated categories
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2009 at 19:20 | vote | accept | alekzander | ||
| Nov 10, 2009 at 20:23 | comment | added | Greg Stevenson | Glad I could help - I'd definitely recommend having a look through the first couple of chapters of Neeman's book. You might also want to look at Krause's notes (which are very good) and/or "A Brown Representability Theorem via Coherent Functors". The paper is short, the result is really nice, and it is used in one of the main results of the Benson-Iyengar-Krause paper you are reading (I know the paper reasonably well ;) ). | |
| Nov 10, 2009 at 19:39 | comment | added | alekzander | Wonderful! I have been meaning to look at Neeman, but have been hesitant, since everything I've tried to look up before in there has been far too .. 'general' may be the best word. | |
| Nov 10, 2009 at 0:37 | comment | added | Greg Stevenson | I hope that helps - sorry I didn't draw the diagrams giving the maps but I don't know how to given the current tex functionality I normally do stuff like that in xypic and I haven't figured out a dodgy solution yet (without using markup). | |
| Nov 10, 2009 at 0:25 | history | edited | Greg Stevenson | CC BY-SA 2.5 |
added more detail; added 262 characters in body
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| Nov 10, 2009 at 0:15 | comment | added | Greg Stevenson | This comes down to the fact that given two distinguished triangles their direct sum is again a triangle - I will edit in a proof. | |
| Nov 10, 2009 at 0:14 | comment | added | alekzander | So my question was why the direct sum X to X+Z to Z to the shift of X (by zero) that you have written there is a triangle. | |
| Nov 9, 2009 at 23:29 | history | edited | Greg Stevenson | CC BY-SA 2.5 |
added 221 characters in body
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| Nov 9, 2009 at 23:13 | history | edited | Greg Stevenson | CC BY-SA 2.5 |
added a reference
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| Nov 9, 2009 at 23:00 | history | answered | Greg Stevenson | CC BY-SA 2.5 |