Timeline for Intersection of Frobenius subalgebra objects
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 30 at 8:01 | vote | accept | Sebastien Palcoux | ||
| Sep 8 at 3:17 | comment | added | Sebastien Palcoux | Here is the connected version: mathoverflow.net/q/478418/34538 | |
| Sep 8 at 1:20 | vote | accept | Sebastien Palcoux | ||
| Sep 22 at 6:37 | |||||
| Sep 7 at 17:08 | history | became hot network question | |||
| Sep 7 at 10:20 | answer | added | Dave Benson | timeline score: 5 | |
| Sep 7 at 10:20 | comment | added | Sebastien Palcoux | @DaveBenson Yes, please. | |
| Sep 7 at 10:16 | comment | added | Dave Benson | Well, it's a finite dimensional commutative $\mathbb{C}$-algebra. Is that good enough for you? The smallest example is five dimensional. Woulld you like me to write out the details? | |
| Sep 7 at 10:15 | comment | added | Sebastien Palcoux | @DaveBenson Could the counterexamples you have in mind be realized as Frobenius algebra objects in a semisimple tensor category over $\mathbb{C}$? | |
| Sep 7 at 9:40 | comment | added | Dave Benson | What is definitely not true is that if you have a finite dimensional Frobenius algebra then the intersection of two Frobenius subalgebras is a Frobenius subalgebra. Even in the commutative case. | |
| Sep 7 at 9:08 | history | asked | Sebastien Palcoux | CC BY-SA 4.0 |