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Sep 10 at 1:22 history rollback Will Sawin
Rollback to Revision 6
Sep 9 at 20:52 history edited Will Sawin CC BY-SA 4.0
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Sep 9 at 20:09 history edited Will Sawin CC BY-SA 4.0
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Sep 9 at 19:28 history edited Will Sawin CC BY-SA 4.0
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Sep 9 at 0:16 comment added H A Helfgott See the answer below.
Sep 8 at 12:57 comment added Will Sawin @HAHelfgott Seems fine to me.
Sep 8 at 3:37 comment added H A Helfgott Given the circumstances, is it socially acceptable to write down the argument on paper, take a picture with my phone and post it below?
Sep 8 at 3:35 comment added H A Helfgott I’ll try to post something soon. (I’m still in Guatemala and my laptop is now refusing to turn on.)
Sep 6 at 1:36 comment added Will Sawin @HAHelfgott It seems that combining the arguments carefully would give that the sum is at most $\epsilon$ for almost all $q$ with at most $C_1 (\epsilon) \sqrt{\log \log N}$ prime factors but can sometimes fail to be at most $\epsilon$ for all $q$ with more than $C_2(\epsilon) \sqrt{\log \log N}$ prime factors for constants $C_1$ and $C_2$ going to $0$ with $\epsilon$. This would be a pretty sharp result and seems worth writing down.
Sep 5 at 23:02 comment added H A Helfgott Ah. Should I give a sketch of the bound for $k=\sqrt{\log \log N}$ below? It still has a wonky step at the beginning, but it can most likely be made rigorous.
Sep 5 at 19:43 comment added Will Sawin @HAHelfgott Thanks! No, what I was trying to express is that the Erdős–Kac argument does not give a good enough bound on the number of large values of $q$ with a small number of prime factors. Of course there are other arguments that estimate that.
Sep 5 at 19:30 comment added H A Helfgott Nice. (I had a piecewise linear function of $\omega(n)$ in my head, but this is simpler.) Your last $>$ should be a $\leq$, right?
Sep 5 at 17:48 history edited Will Sawin CC BY-SA 4.0
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Sep 5 at 17:39 history undeleted Will Sawin
Sep 5 at 17:39 history edited Will Sawin CC BY-SA 4.0
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Sep 5 at 17:34 history deleted Will Sawin via Vote
Sep 5 at 17:33 history edited Will Sawin CC BY-SA 4.0
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Sep 5 at 17:26 history answered Will Sawin CC BY-SA 4.0