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Timeline for A candidate for one-way functions

Current License: CC BY-SA 4.0

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Sep 6 at 1:25 comment added Daniel Weber @EmilJeřábek The sizes of $Y$ and $X$ being equal doesn't matter, as you can just pad them. However, I haven't thought about the vertices of $X$ being regular, you're right
Sep 5 at 20:26 comment added Emil Jeřábek Are you suggesting the problem is NP-complete by Shaeffer's theorem? I don't see how that's supposed to work. Letting $\mathrm{MAJ}_5$ denote majority on 5 variables, $\mathrm{CSP(\{MAJ_5,\neg MAJ_5\})}$ is NP-complete all right, but this is a more general problem, where the sizes of $X$ and $Y$ are unrelated, and vertices of $X$ can have arbitrary degree rather than the graph being 5-regular.
Sep 5 at 15:59 comment added Daniel Weber Then reversing this is NP-complete by the dichotomy theorem, but I don't know about the average case
Sep 5 at 5:48 comment added Arash Ahadi What about 5-majority in random bipartite 5-regular graphs?
Sep 5 at 2:11 history answered Daniel Weber CC BY-SA 4.0