Skip to main content
3 events
when toggle format what by license comment
Sep 2 at 16:30 comment added Andreas Blass Since the question asks about provability in ZF, not ZFC, it seems worth noting that the absence of AC does no harm to this argument, because $L$ is well-orderable even without AC.
Sep 2 at 2:01 vote accept Jesse Elliott
Sep 2 at 0:49 history answered Joel David Hamkins CC BY-SA 4.0