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Aug 26 at 5:59 vote accept Abdelhay Benmoussa
Aug 26 at 11:17
Aug 20 at 10:25 history edited Carlo Beenakker CC BY-SA 4.0
edited body
Aug 20 at 10:02 comment added Carlo Beenakker @PeterTaylor --- wonderful, thanks!
Aug 20 at 10:02 history edited Carlo Beenakker CC BY-SA 4.0
added 78 characters in body
Aug 20 at 9:07 comment added Peter Taylor Looks rather like $$B_n(x) = \sum_{k=1}^{n} \frac{(-1)^{k+1} n! \prod_{i=1}^k(4i-2)}{(n-k)!}z^{2n-2k}$$
Aug 19 at 15:24 history edited Carlo Beenakker CC BY-SA 4.0
added 28 characters in body
Aug 19 at 15:16 history edited Carlo Beenakker CC BY-SA 4.0
added 28 characters in body
Aug 19 at 15:07 history answered Carlo Beenakker CC BY-SA 4.0